{VERSION 2 3 "SGI IRIS UNIX" "2.3" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 } {PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Output" 0 11 1 {CSTYLE "" -1 -1 "" 0 1 180 0 56 0 0 0 0 0 0 0 0 0 0 }3 3 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Plot" 0 13 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 27 "with(plots):\nwith(D Etools):" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 96 "First, lets define a \+ few convenient abbreviations, so we needn't type our equations so verb osely" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 158 "Theta:=theta(t): \+ V:=v(t):\nTdot:=diff(theta(t),t):\nVdot:=diff(v(t),t):\nX:=x(t): Y:=y (t):\nXdot:=diff(x(t),t): Ydot:=diff(y(t),t):\nS:=s(t): Sdot:=diff(s( t),t):" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 209 "First, let's see what the flight of the glider looks lik e for a few different initial angles, but all with the same initial ve locity. Note that here we are using the coordinates with a rescaled t ime variable." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 389 "R:=.2;\nDEplot([\n Tdot= V*(V^2 - cos(Theta))/ V,\n Vdot= V*(-sin(Theta) -R*V^2),\n Xdot= V*V*cos(Theta),\n Ydot= \+ V*V*sin(Theta)],\n[theta,v,x,y],\nt=0..20,v=0..2,theta=-Pi..Pi,\nx=-1. .15, y=-.5..4,\n[[v(0)=2,theta(0)=Pi/4, x(0)=0,y(0)=2], \n [v(0)=2,the ta(0)=0, x(0)=0,y(0)=2],\n [v(0)=2,theta(0)=-Pi/2,\n x(0)=0,y(0)=2]], \n scene=[X,Y],\n stepsize=0.1,\nlinecolor=[red,green,blue],obsrange= false);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"RG$\"\"#!\"\"" }}{PARA 13 "" 1 "" {INLPLOT "6'-%'CURVESG6gw7$7$\"\"!$\"\"#F(7$$\"1+\"G8$[(R1# !#;$\"1Zlcq.ovA!#:7$F+7$$\"1+&z3ib//$F.$\"14+CpUT8DF17$F37$$\"1VT>,'** 3T$F.$\"1*=F+2]Rq#F17$F97$$\"1%\\g\"f]VdMF.$\"1H8*pPnD&GF17$F?7$$\"1JYd[nHF17$FE7$$\"1ttZ,3tLJF.$\"1!>HTWei0$F17$FK7$$\"1A*[ 0Y3^*GF.$\"1-@-N*p\\7$F17$FQ7$$\"1u9&39)\\XEF.$\"1tD)Hm'HyJF17$FW7$$\" 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One way to do this is to set the vector field to 0 if Y ever becomes negative. \+ We can use piecewise to adjust the equations to account for this. Thu s, the picture above becomes" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 457 "R:=.2;\nDEplot([\n Tdot= piecewise(Y>0,V*(V^2 - cos(Theta))/V, 0),\n Vdot= piecewise(Y>0,V*(-sin(Theta) -R*V^2),0),\n Xdot= piecewi se(Y>0,V*V*cos(Theta),0),\n Ydot= piecewise(Y>0,V*V*sin(Theta),0)],\n [theta,v,x,y],\nt=0..20,v=0..2,theta=-Pi..Pi,\nx=-1..15, y=-.5..4,\n[[ v(0)=2,theta(0)=Pi/4, x(0)=0,y(0)=2], \n [v(0)=2,theta(0)=0, x(0)=0,y( 0)=2],\n [v(0)=2,theta(0)=-Pi/2,\n x(0)=0,y(0)=2]],\n scene=[X,Y],\n stepsize=0.1,\nlinecolor=[red,green,blue],obsrange=false);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"RG$\"\"#!\"\"" }}{PARA 13 "" 1 "" {INLPLOT "6'-%'CURVESG6gw7$7$\"\"!$\"\"#F(7$$\"1+\"G8$[(R1#!#;$\"1Zlcq .ovA!#:7$F+7$$\"1+&z3ib//$F.$\"14+CpUT8DF17$F37$$\"1VT>,'**3T$F.$\"1*= F+2]Rq#F17$F97$$\"1%\\g\"f]VdMF.$\"1H8*pPnD&GF17$F?7$$\"1JYd[nHF17$FE7$$\"1ttZ,3tLJF.$\"1!>HTWei0$F17$FK7$$\"1B*[0Y3^*GF.$\" 1-@-N*p\\7$F17$FQ7$$\"1v9&39)\\XEF.$\"1tD)Hm'HyJF17$FW7$$\"1F5yvZ#yR#F 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itFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFait FaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFa itFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFait FaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFaitFait-Fgbn6&FibnF(F (FjbnF]cnFacn-%%VIEWG6$;$!+++++=!\"*$\"++++!e\"F\\cn;$!++++]s!#5$\"+++ +DUFjit-%+AXESLABELSG6$%%x(t)G%%y(t)G" 2 789 389 389 2 0 1 0 2 9 0 4 2 1.000000 45.000000 45.000000 10030 10061 10056 10074 0 0 0 20030 0 12020 0 0 0 0 0 0 0 1 1 0 0 0 123 252 0 0 0 0 0 0 }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 287 "But, in fact, we \+ want to know what the initial angle should be that will allow the glid er to fly exactly 10 units. As a first step toward this, we can let m aple create a procedure that gives us the location of the glider at an y time. To do this, we use dsolve with the numeric option. " }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 304 "fly:=dsolve( [\n Tdot= pie cewise(Y>0,V*(V^2 - cos(Theta))/V,0),\n Vdot= piecewise(Y>0,V*(-sin(T heta) -R*V^2),0),\n Xdot= piecewise(Y>0,V*V*cos(Theta),0),\n Ydot= p iecewise(Y>0,V*V*sin(Theta),0),\n Sdot= piecewise(Y>0,V,0), \n v(0)= 2, theta(0)=0, x(0)=0, y(0)=2, s(0)=0],\n [Theta,V,X,Y,S], type=numer ic);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$flyG:6#%(rkf45_xG6'%\"iG%(r kf45_sG%)outpointG%#r1G%#r2G6#%aoCopyright~(c)~1993~by~the~University~ of~Waterloo.~All~rights~reserved.G6\"C&>8&-%&evalfG6#9$@$52-%$absG6#,$ F3!\"\"-F<6#,&&%,loc_controlG6#\"\"#\"\"\"F3F?4-%'memberG6$&FD6#\"\"'< *F?FG!\"#FF$FF\"\"!$F?FR$FPFR$FGFRC%>FD-%%copyG6#=F06#;FG\"#aE\\[lW\"# GFR\"\"%$FG!\")\"#@FQ\"#ZFR\"\")\"&++$\"#5FR\"#YFR\"#?FR\"\"*\"%+5\"\" $FR\"#XFR\"#8FRFFFR\"#TFR\"#JFR\"#PFR\"#KFR\"#`FRFG\"\"&\"#EFR\"#7FR\" #\\FRFNFG\"#_FR\"#WFRFhnFR\"#^FR\"#;FR\"#AFR\"#SFR\"#MFR\"#FR\"#NFR\"#CFR\"#=FR\"#9FR\"#BFQ\"#UFR>%'loc_y0 G-FY6#=F06#;FGF_pE\\[l&F[oFQFgoFRFFFQFGFRF_pFR>%'loc_y1G-FY6#=F0FgrE\\ [l!@$0F;FRC$>&FD6#FgoF3@%1%'DigitsG-%'evalhfG6#FhsC$>8%-%*traperrorG6# -Fjs6#-%=dsolve/numeric_solnall_rkf45G6,%&loc_FG-%$varG6#FD-Fit6#Fcr-F it6#F[s-Fit6#%'loc_F1G-Fit6#%'loc_F2G-Fit6#%'loc_F3G-Fit6#%'loc_F4G-Fi t6#%'loc_F5G-Fit6#%)loc_workG@$/F^t%*lasterrorGC%>8'-%+searchtextG6$.F js-%(convertG6$-%#opG6$FG7#F^t%%nameG>8(-Fhv6$.%)hardwareGF[w@%50FfvFR 0FdwFR-Fet6,FgtFDFcrF[sFauFduFguFjuF]vF`v-%&ERRORG6#F^tF]x7$/%\"tGF7-% $seqG6$/&%$ordG6#,&8$FGFGFG&Fcr6#F]y/F]yFhrF06%FDFcrF[s" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "fly(20);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#7(/%\"tG\"#?/-%&thetaG6#F%$!1`bA_/-)z\"!#;/-%\"vGF*$\"1 y6@NDd9)*F-/-%\"xGF*$\"1lP5Uk\"eM\"!#9/-%\"yGF*$!1.DA%z#*R;&!#A/-%\"sG F*$\"1%QnDdy7\\\"F8" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 452 " From tha t, we can see that the middle solution (with initial angle 0) goes 13 .458... before it hits the ground. \n Since the initial conditions a re part of the input to the procedure fly, to find out how the final p osition depends on the initial angle would mean calling dsolve again. \+ This is tedious, so we write a little procedure to do it for us. It \+ looks long, but it really is only dsolve followed by evaluating the s olution at a given time." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 889 "whereHit:= proc(theta0) \n local x,y,v,t,s,theta,X,Y,V,S,R,\n \+ Theta,Xdot,Ydot,Vdot,Tdot,Sdot,v0,\n sol,xhit,hittime;\n \+ R:=0.2;\n v0:=2;\n \n Theta:=theta(t): Tdot:=diff(theta(t),t):\n \+ V:=v(t): Vdot:=diff(v(t),t):\n X:=x(t): Xdot:=diff (x(t),t):\n Y:=y(t): Ydot:=diff(y(t),t):\n S:=s(t): \+ Sdot:=diff(s(t),t):\n\n sol:=dsolve(\n [Tdot= piecewise(Y>0 ,V*(V^2 - cos(Theta))/V,0),\n Vdot= piecewise(Y>0,V*(-sin(The ta) -R*V^2),0),\n Xdot= piecewise(Y>0,V*V*cos(Theta),0),\n \+ Ydot= piecewise(Y>0,V*V*sin(Theta),0),\n Sdot= piecewi se(Y>0,V,0),\n x(0)=0, y(0)=2, v(0)=v0, theta(0)=theta0, s(0) =0],\n [x(t),y(t),theta(t),v(t),s(t)],numeric);\n \n hittime := 10;\n while ((subs(sol(hittime)[3],y(t)) > 0)) do\n hittime:= \+ evalf(hittime + 10);\n od;\n\n xhit:=rhs(sol(hittime)[2]);\n RETURN (xhit);\nend:" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 71 "Thus, we can ge t the same answer out of that routine a little simpler:" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 45 "whereH it(-Pi/2);\nwhereHit(0);\nwhereHit(Pi/4);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"1/Mj7E60&)!#:" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\" 11p1Gj\"eM\"!#9" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"1E(4T@y.1\"!#9" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 158 "In fact, if we like, we can ma ke a picture of how the final x value depends on the initial angle by \+ graphing this function. Rather than plotting it directly," }}{PARA 0 "" 0 "" {TEXT -1 50 "it works better to just plot a sequence of values :" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 45 "plot([seq([z/10,whereHit(z/10)],z=-31..31)]);" }} {PARA 13 "" 1 "" {INLPLOT "6#-%'CURVESG6$7[o7$$!1+++++++J!#:$\"1O#R*G+ 65:!#;7$$!\"$\"\"!$\"1#z6&\\0:eDF-7$$!1+++++++HF*$\"1-L;!f$*\\6%F-7$$! 1+++++++GF*$\"14u@!yF%RMF*7$$!1+++++++FF*$\"1vP_Q$4)fNF*7$$!1+++++++EF *$\"14d!*4$\\mp$F*7$$!1+++++++DF*$\"1M()pFGg`QF*7$$!1+++++++CF*$\"1Ac% Qd#ePSF*7$$!1+++++++BF*$\"1pXc@AKjUF*7$$!1+++++++AF*$\"1unw=kQtXF*7$$! 1+++++++@F*$\"1h/Re$o$ppF*7$$!\"#F1$\"1oGZhe)pG(F*7$$!1+++++++>F*$\"1: f]'z9bc(F*7$$!1+++++++=F*$\"1zRh*[+`$yF*7$$!1+++++++)R3;$H\"Fhq7$$!1+++++++SF-$\"1&et4'Hl98Fhq7$$!1+++++++IF-$ \"1&G(emm:K8Fhq7$$!1+++++++?F-$\"1FFpRH(RM\"Fhq7$$!1+++++++5F-$\"1+#3( )yr([8Fhq7$F1$\"11p1Gj\"eM\"Fhq7$$\"1+++++++5F-$\"1!)*3qC#zM8Fhq7$$\"1 +++++++?F-$\"1jv`0Gf:8Fhq7$$\"1+++++++IF-$\"1r87e(Q#)G\"Fhq7$$\"1+++++ ++SF-$\"1B[bH)HID\"Fhq7$$\"1+++++++]F-$\"1cvWDw(3@\"Fhq7$$\"1+++++++gF -$\"1kj7^%HF;\"Fhq7$$\"1+++++++qF-$\"1^Fv]\\P46Fhq7$$\"1+++++++!)F-$\" 1H[z_rv^5Fhq7$$\"1+++++++!*F-$\"1TqgQ,X=**F*7$$\"\"\"F1$\"1!e\\#Q&=(H$ *F*7$$\"1+++++++6F*$\"1_#4*=o(>y)F*7$$\"1+++++++7F*$\"1pvl.I<)G)F*7$$ \"1+++++++8F*$\"1K#*Hy]GZyF*7$$\"1+++++++9F*$\"1EX]CuX_uF*7$$\"1++++++ +:F*$\"1\")[C`G-&4(F*7$$\"1+++++++;F*$\"1Gk\"Hbw^w'F*7$$\"1+++++++F*$\"1]ZM) *)*)Ht&F*7$$\"\"#F1$\"1]c^A&o:(RF*7$$\"1+++++++@F*$\"1N.1*=+Be$F*7$$\" 1+++++++AF*$\"1.f9[\"Q!fLF*7$$\"1+++++++BF*$\"1N&)*)*eH\"4KF*7$$\"1+++ ++++CF*$\"1r!*f/Fa1JF*7$$\"1+++++++DF*$\"13vE()R>RIF*7$$\"1+++++++EF*$ \"1\\33n/5+IF*7$$\"1+++++++FF*$\"1P#*)RU*o%)HF*7$$\"1+++++++GF*$\"1-&G 5n@(*)HF*7$$\"1+++++++HF*$\"1y\\25Z;fq!#<7$$\"\"$F1$\"1`,(*R,#HP&Fd^l7 $$\"1+++++++JF*$\"1pOa#[tk8*Fd^l-%'COLOURG6&%$RGBG$\"#5F`rF1F1" 2 812 464 464 2 0 1 0 2 9 0 4 2 1.000000 45.000000 45.000000 10030 10061 10056 10074 0 0 0 20030 0 12020 0 0 0 0 0 0 0 1 1 0 0 0 255 171 0 0 0 0 0 0 }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 174 "A good graph would need \+ some more points near -3 and +2, but this is good enough to let us kno w that we should concentrate near the angles .8 and .9, or between - 1.4 and -1" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "whereHit(.8); whereHit(.9);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"1H[z_rv^5!#9" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#$\"1TqgQ,X=**!#:" }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 160 "We could just try values until we get what we wan t, but we can do this more efficiently using bisection, trapping the v alue we are looking for and narrowing in." }}{PARA 0 "" 0 "" {TEXT -1 67 "Here is a little maple procedure to do that for a general function ." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 708 "bisect:=proc(f,xlow_i n,xhi_in,epsilon)\n local xlow, xmid, xhi, flow, fmid, fhi;\n \n \+ xlow := xlow_in; flow:= f(xlow);\n xhi := xhi_in; fhi := f(xh i);\n\n if (sign(flow) = sign(fhi)) then\n printf( `[%g,%g] an d [%g,%g] dont bracket a zero\\n`,\n evalf(xlow), evalf( flow), evalf(xhi), evalf(fhi));\n RETURN();\n fi;\n\n \n w hile( evalf(abs(xhi-xlow)) > evalf(epsilon)) do\n xmid := evalf(( xlow+xhi)/2);\n fmid := f(xmid);\n # print([xlow,flow], [xmid ,fmid], [xhi,fhi]);\n if (sign(fmid) = sign(fhi)) then\n \+ xhi := xmid; \n fhi := fmid;\n else\n \+ xlow:= xmid;\n flow:= fmid;\n fi; \n od;\n RETUR N(xmid);\nend:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 45 "bisect(x- >whereHit(x)-10.0, .8, .9, 0.00001);" }}{PARA 11 "" 1 "" {XPPMATH 20 " 6#$\"+zn>k))!#5" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 47 "bisect(x ->whereHit(x)-10.0, -1, -1.5, 0.00001);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$!+'H*3o7!\"*" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 75 "So now, we can see them both flying merrily along, and landing right at 10." }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 416 "R:=.2;\nDEplot([\n Tdot= p iecewise(Y>0,V*(V^2 - cos(Theta))/V,0),\n Vdot= piecewise(Y>0,V*(-sin (Theta) -R*V^2),0),\n Xdot= piecewise(Y>0,V*V*cos(Theta),0),\n Ydot= piecewise(Y>0,V*V*sin(Theta),0)],\n[theta,v,x,y],\nt=0..20,v=0..2,the ta=-Pi..Pi,\nx=-1..11, y=0..3.5,\n[[v(0)=2,theta(0)=.88642, x(0)=0,y(0 )=2], \n [v(0)=2,theta(0)=-1.2681, x(0)=0,y(0)=2]],\n scene=[X,Y],\n \+ stepsize=0.1,\nlinecolor=[red,blue],obsrange=false);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"RG$\"\"#!\"\"" }}{PARA 13 "" 1 "" {INLPLOT "6&-% 'CURVESG6gw7$7$\"\"!$\"\"#F(7$$\"1])G.sj6(=!#;$\"1/_([)oBW;!#:7$F+7$$ \"1f\\J\"psl\"[F.$\"1V>fCS?t8F17$F37$$\"1G$HyV&*>G)F.$\"1TKe4Vx77F17$F 97$$\"1zdR4%GJ<\"F1$\"1\"R&4qvbc6F17$F?7$$\"1zfyfOT\"[\"F1$\"1^Q\\Mo#z <\"F17$FE7$$\"1z.M:Y**QF1$\"1Nb 4p0rO8F17$FQ7$$\"1'z!f?A$*4@F1$\"1ga3r6*GV\"F17$FW7$$\"1!4\\$*GA!RAF1$ \"1))\\s4@SD:F17$Fgn7$$\"1g$>i))Q9M#F1$\"1'**eWXa'4;F17$F]o7$$\"1jGK_ \")pBCF1$\"1Cn#o.RRo\"F17$Fco7$$\"1-?**)*yz!\\#F1$\"1Vq\"G_@\"[F17$Faq7$$\"1_VJg3t*p#F1$\"1w<5RvEZ>F17$Fgq7$$\"1c>[CIUFFF1$\"1:% pT[c&p>F17$F]r7$$\"1$Hw7d$[_FF1$\"1s0N_J*y)>F17$Fcr7$$\"1'*)G;W8ax#F1$ 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