A

B

D

E

F

G

C

X

(X-mean)^2

Mean

Variance

Standard Dev

|X-Mean|

Average. dist mean.

Circle with radius Standard Deviation

This app computes mean and standard deviation of 
of the points A, B, C, D, E and F. 
You can drag the points and see how the values of the
mean and standard deviation vary.
Is it possible to have all the points instead of the interval
centered at the mean, and of size twice the standard
deviation?

The length of each of the green segments is the distance
of the corresponding point to the mean.

Explanation 2

B = Point(xAxis)
B4: x(B)
A = Point(xAxis)
C = Point(xAxis)
D = Point(xAxis)
E = Point(xAxis)
F = Point(xAxis)
B3: x(A)
B5: x(C)
B6: x(D)
B7: x(E)
B8: x(F)
B11 = Mean(B3:B8)
C3: (B3 - $B$11)^(2)
C4: (B4 - B11)^(2)
C5: (B5 - B11)^(2)
C6: (B6 - B11)^(2)
C7: (B7 - B11)^(2)
C8: (B8 - B11)^(2)
D3: abs(B3 - $B$11)
D4: abs(B4 - $B$11)
D5: abs(B5 - $B$11)
D6: abs(B6 - $B$11)
D7: abs(B7 - $B$11)
D8: abs(B8 - $B$11)
C11 = Mean(C3:C8)
C13: sqrt(C11)
D13 = Mean(D3:D8)
A17 = 2
a: x = B11
A_1 = Point({x(A), 1})
A_2 = Point({B11, 1})
B_1 = Point({x(B), 2})
C_1 = Point({x(C), 3})
C_2 = Point({B11, 3})
B_2 = Point({B11, 2})
D_1 = Point({x(D), 1.5})
D_2 = Point({B11, 1.5})
E_1 = Point({x(E), 2.5})
E_2 = Point({B11, 2.5})
F_1 = Point({x(F), 3.5})
F_2 = Point({B11, 3.5})
b = Segment(A_2, A_1)
c = Segment(D_2, D_1)
d = Segment(B_1, B_2)
e = Segment(E_2, E_1)
f = Segment(F_2, F_1)
g = Segment(C_1, C_2)
G = Intersect(a, xAxis)
k = Circle(G, (2 * C13))
h = false
p = Circle(Point[{B11, 0}], C13)
Explanation = false
i = false